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Subject: Buford

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Jim    Posted 01-13-2018 at 10:43:35 [URL] [DELETE]        [Reply] [Email]  
  • Buford
  • With a torque requirement of 450 lbs on the axle nut how do you guys get it there or do you? My torque wrench doesn't go that high-250 lbs. Thanks

    Bruce(OR)    Posted 01-14-2018 at 14:03:12 [URL] [DELETE]        [Reply] [No Email]  
  • Re: Buford
  • Simple thinking will get you there on any torque situation. Ft Lb is simply the amount of force needed at a 1 ft distance.
    So you need 450 pounds of force at 1 foot.
    225 pounds at 2 feet,
    112.5 at 4 feet.
    56.25 pounds at 8 feet.
    Wanna get your grand child to do it?
    28.125 pounds at 16 feet away.

    Inch pounds is in inches and so it goes.

    Jim    Posted 01-14-2018 at 14:35:24 [URL] [DELETE]        [Reply] [Email]  
  • Re: Buford
  • I guess I am still not clear. Say I snug the nut only but then apply force at 4 feet. How far would I need the lever to move in order to know I have applied the 112.5 ft pounds?

    Bruce(OR)    Posted 01-14-2018 at 21:26:29 [URL] [DELETE]        [Reply] [No Email]  
  • Re: Buford
  • Hanging a 4 foot bar on it is easy enough. Now hang 112.5 pounds on the end of the bar. When the bar stops moving downward, it is torqued.
    450 Ft lbs of torque is 450 pounds at 1 foot away. Division get's you to 112.5 pounds of downward force.

    Jim    Posted 01-14-2018 at 22:40:56 [URL] [DELETE]        [Reply] [Email]  
  • Re: Buford
  • Thanks again for your help. I have an extendable 3/4 inch drive breaker bar that goes out to 40". I can come close enough with that leverage I would think.

    Dean    Posted 01-14-2018 at 15:03:19 [URL] [DELETE]        [Reply] [No Email]  
  • Re: Buford
  • Distance depends upon how tight the nut is initially and is not important.

    Simply apply 112.5 pounds of force to the lever at 4' from the center of the axle until the nut no longer turns.


    Jim    Posted 01-14-2018 at 17:17:20 [URL] [DELETE]        [Reply] [Email]  
  • Re: Buford
  • Thanks. I get it now. Thanks for reiteration.

    Jim    Posted 01-14-2018 at 14:15:04 [URL] [DELETE]        [Reply] [Email]  
  • Re: Buford
  • Thanks Bruce. I think I will get my two big grandsons to do it. Get them away from computer games.

    John in MIch    Posted 01-13-2018 at 13:49:02 [URL] [DELETE]        [Reply] [No Email]  
  • Re: Buford
  • I use a 3/4 drive socket breaker bar with a 2" socket and a 4 foot pipe. I put a "calibrated" (swag) 112 pounds of pressure on the end of the pipe. Then, I adjust the nut to align the clip retainer hole to the axle. Never snapped a nut, stripped a nut or axle shaft. LOL

    Dean    Posted 01-13-2018 at 11:02:15 [URL] [DELETE]        [Reply] [No Email]  
  • Re: Buford
  • You've posted in the Politics Forum, no doubt by mistake, but I'll answer here.

    Unless you have a 450+ Lb/Ft torque wrench, you will need to improvise.

    I use a 2 1/2" combination wrench (use the box end). I lock both brakes, put the tractor in first gear,, Sherman underdrive and jump up and down on the end of the wrench until it tightens the nut no more. Works for me.

    Yes, you could use a pipe or other extension on a large wrench or socket and apply a known force at a known distance from the axle center to be more accurate, but such is not necessary.


    Jim    Posted 01-13-2018 at 11:49:11 [URL] [DELETE]        [Reply] [Email]  
  • Re: Buford
  • Thanks Dean.

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